Slash McCoy
I freehand dog rockets
There seems to be some confusion as to exactly how the bevel
angle of a razor is measured. I will call everyone's
attention to the basic formulae for solving a right triangle.
(A triangle having one 90 degree angle)
Sine of the angle = Opposite side / Hypotenuse
Cosine of the angle = Adjacent side / Hypotenuse
Tangent of the angle = Opposite side / Adjacent side
These formulae only hold for a right triangle. They may not
be applied to an isosceles triangle. To solve an isosceles
triangle, it must be broken into two right triangles, which
can be solved using the simple formulae above. To measure and
calculate using just the spine thickness and the blade width
is wrong on several counts. First of all, it assumes a right
triangle, and the spine thickness and blade width actually
form an isosceles triangle. Second, the thickest part of the
spine is not separated from the edge by the width of the
blade, but by a distance somewhat less than that. Third, the
thickest part of the spine might not in fact lie on the bevel
plane, but could conceivably lie somewhere inside the bevel.
And I have been as guilty as everyone else in using imprecise
methods of calculation using irrelevant measurements.
.
.
The illustration is a rough and ready representation of a
full hollowground razor. Notice the flat bevel at the edge,
and a flat bevel on the spine which is obviously the same
bevel. More or less to scale, the razor is a 6/8, with a
spine thickness of about 11/64". The bevel angle is 15
degrees. Ohhh, sharp, huh? Now, we want to calculate the
bevel angle, right? We must split the isosceles triangle into
two right triangles along the center plane of the blade. Each
triangle will then have 1/2 the spine thickness as the
OPPOSITE SIDE. Now we need either the ADJACENT or the
HYPOTENUSE to solve for either Sine or Tangent. Obviously,
measuring the ADJACENT side accurately will be awkward. I
prefer to measure the HYPOTENUSE. The best way I have found
to do this is to select a point on the spine and the edge an
inch or so from the tip. Hit it with a sharpie, trying to
leave the ink wet. Quickly before the ink dries, rest the
blade tip on a piece of flat stretched paper so that the
spine and edge are both in contact. Rock the blade down so
the sharpie ink on the spine and the edge make an imprint on
the paper. Then it is a simple matter to measure the greatest
distance between the marks with a dial caliper.
The overall blade width in the illustration is 600 pixels.
Scaled, that is 6/8 or 3/4". But remember, that measurement
is irrelevant. The ADJACENT side of the triangle is 532
pixels long in the illustration, but in the real world it
would be awkward to measure precisely. The hypotenuse is 539
pixels long in the illustration, about 43/64". The OPPOSITE
side happens to be half the spine thickness in this example,
11/128". Going with the Sine formula, S = 0 / H, so the Sine
= 11/128 / 43/64 = 0.1279, and the inverse sin function on
the calculator says that this is the sine for an angle of
7.34 degrees. Doubling this to get the entire bevel angle
gives a calculated bevel of 14.7 degrees. A little off, but
write it off to the pixels and the twidgety widgety up and
down scaling and stuff. .3 degrees is actually kind of small
potatoes, anyhow. A real world measurement, accurately taken,
then properly calculated, will probably give a much more
accurate determination of bevel angle. Oh, and my drawn bevel
line could have been a bit off, too. Darn pixels.
Now, if you had done what many do, and divided the spine
thickness by the blade width, you would have got a sine of
0.229 and a bevel angle of 13.2 degrees. Quite a difference,
huh? One angle should shave. The other would probably not
keep an edge worth a darn. And horrors... you might think the
spine should get about 4 layers of tape when honing! Of
course this would give you a secondary compound bevel of
about 18 degrees... still sort of shave-able but the actual
15 degree original bevel was pretty close to ideal.
Please, anybody with anything to add go ahead and throw your
two centavos in the ring.
angle of a razor is measured. I will call everyone's
attention to the basic formulae for solving a right triangle.
(A triangle having one 90 degree angle)
Sine of the angle = Opposite side / Hypotenuse
Cosine of the angle = Adjacent side / Hypotenuse
Tangent of the angle = Opposite side / Adjacent side
These formulae only hold for a right triangle. They may not
be applied to an isosceles triangle. To solve an isosceles
triangle, it must be broken into two right triangles, which
can be solved using the simple formulae above. To measure and
calculate using just the spine thickness and the blade width
is wrong on several counts. First of all, it assumes a right
triangle, and the spine thickness and blade width actually
form an isosceles triangle. Second, the thickest part of the
spine is not separated from the edge by the width of the
blade, but by a distance somewhat less than that. Third, the
thickest part of the spine might not in fact lie on the bevel
plane, but could conceivably lie somewhere inside the bevel.
And I have been as guilty as everyone else in using imprecise
methods of calculation using irrelevant measurements.
.
The illustration is a rough and ready representation of a
full hollowground razor. Notice the flat bevel at the edge,
and a flat bevel on the spine which is obviously the same
bevel. More or less to scale, the razor is a 6/8, with a
spine thickness of about 11/64". The bevel angle is 15
degrees. Ohhh, sharp, huh? Now, we want to calculate the
bevel angle, right? We must split the isosceles triangle into
two right triangles along the center plane of the blade. Each
triangle will then have 1/2 the spine thickness as the
OPPOSITE SIDE. Now we need either the ADJACENT or the
HYPOTENUSE to solve for either Sine or Tangent. Obviously,
measuring the ADJACENT side accurately will be awkward. I
prefer to measure the HYPOTENUSE. The best way I have found
to do this is to select a point on the spine and the edge an
inch or so from the tip. Hit it with a sharpie, trying to
leave the ink wet. Quickly before the ink dries, rest the
blade tip on a piece of flat stretched paper so that the
spine and edge are both in contact. Rock the blade down so
the sharpie ink on the spine and the edge make an imprint on
the paper. Then it is a simple matter to measure the greatest
distance between the marks with a dial caliper.
The overall blade width in the illustration is 600 pixels.
Scaled, that is 6/8 or 3/4". But remember, that measurement
is irrelevant. The ADJACENT side of the triangle is 532
pixels long in the illustration, but in the real world it
would be awkward to measure precisely. The hypotenuse is 539
pixels long in the illustration, about 43/64". The OPPOSITE
side happens to be half the spine thickness in this example,
11/128". Going with the Sine formula, S = 0 / H, so the Sine
= 11/128 / 43/64 = 0.1279, and the inverse sin function on
the calculator says that this is the sine for an angle of
7.34 degrees. Doubling this to get the entire bevel angle
gives a calculated bevel of 14.7 degrees. A little off, but
write it off to the pixels and the twidgety widgety up and
down scaling and stuff. .3 degrees is actually kind of small
potatoes, anyhow. A real world measurement, accurately taken,
then properly calculated, will probably give a much more
accurate determination of bevel angle. Oh, and my drawn bevel
line could have been a bit off, too. Darn pixels.
Now, if you had done what many do, and divided the spine
thickness by the blade width, you would have got a sine of
0.229 and a bevel angle of 13.2 degrees. Quite a difference,
huh? One angle should shave. The other would probably not
keep an edge worth a darn. And horrors... you might think the
spine should get about 4 layers of tape when honing! Of
course this would give you a secondary compound bevel of
about 18 degrees... still sort of shave-able but the actual
15 degree original bevel was pretty close to ideal.
Please, anybody with anything to add go ahead and throw your
two centavos in the ring.