- Thread starter
- #81
Yes, Bluesman, but...
I may be wrong here, but a smile is a different thing that what I'm talking about. The smile on your razor is just the edge protruding straight out in a belly shape. That's not a warp. The smiling razor is still flat all along the plane that rests on the hone.
You put a smiling razor on a piece of flat glass and add water, the flat razor will get stuck to the glass. You will have just as much stiction as if it was not smiling.
But Jarrod's Ark is creating a curve along a plane that the flat plane of your smiling razor is trying to rest on.
So far I have found no stiction. And that conforms to the theory. You start your stroke heel leading, with only the heel touching the stone. And way back down the curve of the stony hill, the toe is hanging up in the air.
I'm exaggerating this to make the point.
By the time you have gone up and down the hill on the other side, the toe is now touching the stone and the heel is up in the air. Air is under more than half of the razor, so no vacuum, no suction.
When you do an x stroke on a convex, this just happens on its own. I'm not doing it myself. The hill does it. I am now starting to sense the pressure starting at the heel and as I stroke, the pressure moves down the razor to finish on the toe. Like how you can feel the edge of a chef's knife running down a chef's steel as you stroke.
And here's the weird thing. Maybe the lack of stiction doesn't matter. On flat stones Stiction tells you all is good. Your hone is flat, so hooray, you don't need to lap it. Your razor does not have a warp, so hooray you don't need to manually do a rolling x. The tell of stiction is my friend on my flat stones.
But on a convex, you don't need to be told about flatness because it's deliberately not flat and you're not going to lap it anyway. And you don't need to be told about a warp, because a warp won't matter, the edge is running along the hone point by point.
I may be wrong here, but a smile is a different thing that what I'm talking about. The smile on your razor is just the edge protruding straight out in a belly shape. That's not a warp. The smiling razor is still flat all along the plane that rests on the hone.
You put a smiling razor on a piece of flat glass and add water, the flat razor will get stuck to the glass. You will have just as much stiction as if it was not smiling.
But Jarrod's Ark is creating a curve along a plane that the flat plane of your smiling razor is trying to rest on.
So far I have found no stiction. And that conforms to the theory. You start your stroke heel leading, with only the heel touching the stone. And way back down the curve of the stony hill, the toe is hanging up in the air.
I'm exaggerating this to make the point.
By the time you have gone up and down the hill on the other side, the toe is now touching the stone and the heel is up in the air. Air is under more than half of the razor, so no vacuum, no suction.
When you do an x stroke on a convex, this just happens on its own. I'm not doing it myself. The hill does it. I am now starting to sense the pressure starting at the heel and as I stroke, the pressure moves down the razor to finish on the toe. Like how you can feel the edge of a chef's knife running down a chef's steel as you stroke.
And here's the weird thing. Maybe the lack of stiction doesn't matter. On flat stones Stiction tells you all is good. Your hone is flat, so hooray, you don't need to lap it. Your razor does not have a warp, so hooray you don't need to manually do a rolling x. The tell of stiction is my friend on my flat stones.
But on a convex, you don't need to be told about flatness because it's deliberately not flat and you're not going to lap it anyway. And you don't need to be told about a warp, because a warp won't matter, the edge is running along the hone point by point.